calculate the sum of angles of a polygon 10 side using the formula (2n-4)into90
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We know that if a polygon has 'n' sides, then it is divided into (n – 2) triangles. We also know that, the sum of the angles of a triangle = 180°. Therefore, the sum of interior angles of a polygon having n sides is (2n – 4) right angles. Thus, each interior angle of the polygon = (2n – 4)/n right angles.
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Step-by-step explanation:
We know that if a polygon has 'n' sides, then it is divided into (n - 2) triangles. We also know that, the sum of the angles of a triangle = 180°. Therefore, the sum of interior angles of a polygon having n sides is (2n- 4) right angles. Thus, each interior angle of the polygon = (2n - 4)/n right angles.
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