Question

calculate the sum of angles of a polygon with 24 sides​

Answer 1

Answer:

The formula for the sum of the interiorangles of a polygon is (n−2)⋅180 , where n is the number of sides. For a24 -gon, n=24 . (24−2)⋅180=3960

Answer 2

$\huge\boxed{\mathbb{\underline{\underline{GIVEN}}}}$

$\textbf{A\:polygon\:with\:24\:sides\:.}$

$\huge\boxed{\mathcal\red{\underline{\underline{To\: calculate}}}}$

$\textbf{Sum\:of\:polygon\:with\:24\:sides}$

$\huge\boxed{\mathfrak\pink{\underline{\underline{Answer}}}}$

$\textsf{Interior angle sum of a polygon with 24\: sides }$

$\textsf{ \:= \:(\:2\:\times\:4\:)\:\times\:90^{\circ} }$

$\Longrightarrow\textsf{ 44\:\times\:90^{\circ} }$

$\Longrightarrow\textsf{ 3960^{\circ} }$

$\huge\texttt{The\:Answer\:is}$

$\huge\texttt{ 3960^{\circ} }$

$\huge\boxed{\mathcal\green{\underline{NOTE}}}$

$\huge\odot$$\:\textsf{Sum of interior angles of }$

$\textsf{a polygon = {2n-4}\times{{90}^{\circ}}\:or\:{n-2}\times{{180}^{\circ}} }$

$\texttt{where n is the number of sides of the polygon}$