Math, asked by bharathkumar72, 7 months ago

Calculate the sum of the zeroes, product of the zeroes and sum of the product of zeroes
taken two at a time for the polynomial 2x cube - 4x square+ 1.​

Answers

Answered by joelpaulabraham
0

Answer:

p + q + r = 2

pq + qr + pr = 0

pqr = -1/2

Step-by-step explanation:

2x³ - 4x² + 1

= 2x³ - 4x² + 0x + 1

= ax³ + bx² + cx + d

where a = 2, b = -4, c = 0, d = 1

Let the be p, q and r

We know that,

Sum of zeroes = -b/a

p + q + r = -(-4)/2 = 4/2

Thus,

p + q + r = 2

also,

Sum of product of zeroes taken two at a time = c/a

pq + qr + pr = 0/2 = 0

also,

Products of zeroes = -d/a

p × q × r = -(1)/2

pqr = -1/2

Hence,

p + q + r = 2

pq + qr + pr = 0

pqr = -1/2

Hope you understood it........All the best

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