Calculate the sum of the zeroes, product of the zeroes and sum of the product of zeroes
taken two at a time for the polynomial 2x cube - 4x square+ 1.
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Answer:
p + q + r = 2
pq + qr + pr = 0
pqr = -1/2
Step-by-step explanation:
2x³ - 4x² + 1
= 2x³ - 4x² + 0x + 1
= ax³ + bx² + cx + d
where a = 2, b = -4, c = 0, d = 1
Let the be p, q and r
We know that,
Sum of zeroes = -b/a
p + q + r = -(-4)/2 = 4/2
Thus,
p + q + r = 2
also,
Sum of product of zeroes taken two at a time = c/a
pq + qr + pr = 0/2 = 0
also,
Products of zeroes = -d/a
p × q × r = -(1)/2
pqr = -1/2
Hence,
p + q + r = 2
pq + qr + pr = 0
pqr = -1/2
Hope you understood it........All the best
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