Calculate the surface area of a hemispherical dome of a temple with radius 14m to be white washed from outside
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Hi ,
Let the radius of the
hemispherical dome ( r ) = 14 m
We know that ,
___________________________
Surface area of the hemispher =
A = 2 × pi × r^2
___________________________
A = 2 × ( 22 / 7 ) × ( 14 )^2
= 2 × ( 22 / 7 ) × 14 × 14
= 1232 m^2
Therefore ,
Curved surface area of the
hemispherical dome = 1232 m^2
I hope this helps you.
:)
Let the radius of the
hemispherical dome ( r ) = 14 m
We know that ,
___________________________
Surface area of the hemispher =
A = 2 × pi × r^2
___________________________
A = 2 × ( 22 / 7 ) × ( 14 )^2
= 2 × ( 22 / 7 ) × 14 × 14
= 1232 m^2
Therefore ,
Curved surface area of the
hemispherical dome = 1232 m^2
I hope this helps you.
:)
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