Question

calculate the temparature of 6.0 moles of a gas occupying 4dm³ at 2 bar presaure.(R=0.0825/dm³k^-mol)

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Answer 1

Answer:

Given,

Amount of the gas ,n = 4.0 mol

Volume of the gas ,V = 5 dm3

Pressure of the gas,p = 3.32 bar

R = 0.083 bar dm3 K–1 mol–1

From the ideal gas equation, we get

pV = nRT

⇒ T = pV / nR

= (3.32x5) / (4x0.083)

= 50K

Hence, the required temperature is 50 K.