Question

Calculate the temperature above which the reduction of lead oxide to lead in the following reaction becomes spontaneous

Answer 1

Answer:

Below is the answer.

Explanation:

The formula of Entropy and Gibbs free reaction is:

ΔS = ΔH/T But Since we want to find the temperature of lead oxide reduction of lead oxide leading to a spontaneous reaction it will be used as such:

T = ΔH/ΔS  

In the reaction, ΔH = 108.4 kJ /mol= 108.4 x 103 J/mol

ΔS=  190 J/K mol

By putting values in their places we get:

S = 108.4 x 103 / 190 = 570.5K  

Hence if Temperature (T) is greater than 570.5K it becomes a spontaneous reaction. As TΔS is greater than ΔH and so ΔG = ( ΔH-TΔS) will be negative and the reaction becomes spontaneous.