Question

Calculate the temperature above which the reduction reaction becomes spontaneous. PbO (g) + C (g) → Pb (s) + CO(g) [ Δ H = 108.4 KJ/mol & Δ S = 190 J K-1 mol-1]​

Answer 1

Answer:

Explanation:ΔG=ΔH−TΔS=0

or T=ΔHΔS=108.4190×10−3=570.5K

Reaction will be spontaneous at temperature higher than 570.5K,