Question

calculate the temperature at which a gas 'A' at 20°C having a volume of 500 cc. will occupies
a volume 250cc​

Answer 1

Given :

• Volume occupied by gas "A" at 20° C = 500 cc

To Find :

• The temperature at which it occupies 250 cc

Solution :

Assuming the pressure to be constant and applying Charles law ,

$\\ \star \: {\boxed{\purple{\sf{ \frac{V_1}{T_1} = \frac{V_2}{T_2} }}}}$

We have ,

• V₁ = 500 cc , T₁ = 20° C = 273 + 20 = 293 K
• V₂ = 250 cc , T₂ = ?

Substituting the values we have in the formula ,

$\\ : \implies \sf \: \frac{500}{293} = \frac{250}{T_2}$

$\\ : \implies \sf \: 293\times 250= 500\times T_2$

$\\ : \implies \sf \: 500T_2 = 73250$

$\\ : \implies \sf \: T_2 = \frac{73250}{500}$

$\\ : \implies{\underline{\boxed {\pink{\mathfrak{T_2 = 146.5\:K }}}}} \: \bigstar$

Hence ,

• The temperature at which gas "A" occupies 250 cc is 146.5 K

Answer 2

Answer:

Given :-

• Volume occupied by gas "A" at 20° C = 500 cc

To Find :-

The temperature at which it occupies 250 cc

Solution :-

Here,we will use Charles Law

$\bf \orange{ \frac{t_1}{v_1} = \frac{t_2}{v_2}}$

V₁ = 500 cc , T₁ = 20° C = 273 + 20 = 293 K

V₂ = 250 cc

Let the other be x

$\tt \implies \frac{500}{293} = \frac{250}{x}$

$\tt \implies \: 500 \times x = 250 \times 293$

$\tt \implies \: 73250 = 500x$

$\tt \implies \: x = \dfrac{73250}{500}$

$\mathfrak \red{x = 146.5 \: k}$

The temperature at which gas 'A' occupies 250 cc is 146.5 K