Question

Calculate the temperature at which a perfect black body radiates energy at the rate of 5.67 w cm raised to -1

Answer 1

Hey dear,

◆ Answer-
T = 1000 K

◆ Explaination-
# Given-
E = 5.67 W/cm^2 = 5.67×10^4 W/m^2

# Solution-
According to Boltzmann's law of radiation,
E = σT^4
T^4 = E / σ
T^4 = 5.67×10^4 / 5.67×10^-8
T^4 = 10^12
T = 10^3 = 1000 K

Therefore, temperature of the black body must be 1000 K.

Hope it helps...

Answer 2

All objects emit electromagnetic radiation according to their temperature. A black body is an idealized object that absorbs all electromagnetic radiation