Question

Calculate the temperature at which an ideal gas has a concentrated of one mole per litre exert a pressure of 1.0 atm

Answer 1

Explanation:

Ideal Gase => Pv = nRT

pressure = p = 1atm

Volume = v = 22.414 (approximate value) 22.4679 ( accurate value )

N = no. of moles = 1

R = gase constant = 0.0823

T = temperature = ?

v = nRt÷p

22.414 = 1 x 0.0823 x t ÷ 1

22.414 = 0.0823 x t ÷ 1

22.414÷0.0823 = t÷1

272.3450 = t ( accurate solution )

Note : 273 K = 0°

t = 0° or 273k ( approximate value )

Therefore, temperature is 0° or 273k

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