Calculate the temperature at which the reading on the
Farenhit scale is double the reading on the selsius
scale
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2
Answer:
320°F
Explanation:
let required temperature be x ° C
therefore, 1°F=2x°C (given)
°F = 9/5 °C+32
2x = 9/5 × x + 32
2x - 9/5× x = 32
10x-9x/5 = 32
x/5 = 32
therefore, x = 160°C
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