Question

Calculate the temperature in °C at which r.m.s velocity of O2 gas molecules will be 1 km/s. Given that R=8.311 J/mol K

Answer only if you are sure of it.​

Answer 1

Apply formula, Vrms =

$\sqrt{3rt \div m}$

where, r = universal gas constant

t = temperature

m = mass of the gas

By putting in formula, Vrms =

$\sqrt({3 \times 8.3 \times t}) \div 32$

Vrms = (1000m/s)^2 = 3× 8.3× t /32

By solving, t = 12,00,000 k or 1199726.85 °C

hope this will help you.

Answer 2

Answer:

given,

molar mass=32kg/mol

Vrms=√3RT/M

1000m/s=√3(8.311) T/32

1000m/s=3(8.311) T/32

T=32(1000000)/3(8.311)

T=1283440K

T=-1283167°C