Calculate the temperature (in °C) at which the
r.m.s velocity of O, gas molecule will be
0.5 kms Given R-8311/mol K
Answers
Answered by
0
Answer:
Given that V
rms
(O
2
)=V
rms
(N
2
)
⇒
M
1
3RT
1
=
M
2
3RT
2
Where M
1
is Molar mass of O
2
= 32
and M
2
is Molar mass of N
2
= 28
thus O
2
is at T
1
temperature
⇒N
2
is at T
2
=373K temperature.
T
1
=
M
2
M
1
×T
2
T
1
=
28
32
×373
T
1
=426.3K
Answered by
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Answer:
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