Calculate the temperature of 2 moles of a gas occupying a volume of 5l at 2.46
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n=2 ,v=5 and p=2.46
so,
by ideal gas equation,
pv=nrt
2.46×5=2×8.31×t
t=2.46×5÷2×8.31
t=
so,
by ideal gas equation,
pv=nrt
2.46×5=2×8.31×t
t=2.46×5÷2×8.31
t=
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