Question

Calculate the temperature of 4.0 mol of a gas occupying 5 dm3 at 3.32 bar.
(R = 0.083 bar dm^3k^-1mol^-1)
​

Answer 1

$\huge\underline{\underline{\bf \orange{Question-}}}$

Calculate the temperature of 4.0 mol of a gas occupying 5 dm3 at 3.32 bar.

${\sf (R=0.083\:bardm^3K^{-1}mol^{-1})}$

$\huge\underline{\underline{\bf \orange{Solution-}}}$

$\large\underline{\underline{\sf Given:}}$

• Mole (n) = 4
• Volume ( V ) = 5 dm³
• Pressure ( P ) = 3.32 bar
• Gas Constant (R) = ${\sf 0.083\:bardm^3K^{-1}mol^{-1}}$

$\large\underline{\underline{\sf To\:Find:}}$

• Temperature (T)

$\large{\rm We \: Know \: That - }$

✪$\large{\boxed{\bf \blue{PV=nRT} }}$

$\implies{\sf 3.32×5=4×0.083×T}$

$\implies{\sf 16.6=0.332×T }$

$\implies{\sf T = \dfrac{16.6}{0.332}}$

$\implies{\bf \red{Temperature (T)=50\:K} }$

$\huge\underline{\underline{\bf \orange{Solution-}}}$

Temperature is ${\bf \red{50K}}$ .

Answer 2

Answer:

The temperature is 50K........