Question

Calculate the temperature of 4.0 mol of a gas occupying 5 dm₃ at 3.32 bar. (R = 0.083 bar dm³ K⁻¹ mol⁻¹).

Answer 1

hope it will help you

Answer 2

Dear Student,

◆ Answer -

T = 50 K

● Explaination -

# Given -

n = 4 mol

V = 5 dm3

P = 3.32 bar

# Solution -

Applying ideal gas equation -

PV = nRT

T = PV/nR

T = 3.32 × 5 / (4 × 0.083)

T = 3.32 × 5 / 0.332

T = 10 × 5

T = 50 K

Therefore, temperature of the given gas is 50 K.

Thanks dear. Hope this helps you...