Question

Calculate the temperature of 4.0 mole of a gas occupying 5 $dm^{3}$ at 3.32 bar. (R = 0.083 bar $dm^{3}$ $K^{-1}$ $mol^{-1}$).

Answer 1

From the given question, in order to calculate the temperature of 4 moles of a gas which is occupying 5 decimetre cube, we need to use the ideal gas equation.

The equation is expressed as,

                                                  PV = nRT.

In this equation we need to take the universal gas constant R as points 3 bar, the temperature should be taken in kelvin as it is the standard unit for temperature.

The calculations are as follows :

We know,

PV = nRT

Rearranging the equation,

$T=\frac{PV}{nR}$

$=\frac{3.32(5)}{4(0.083)}=50K$