Question

calculate the temperature of 4.0 mole of a gas occurring 5 DM cube at 3.32 bar ​

Answer 1

If gas is assumed to be ideal then

Use ideal gas equation Pv= nRT

T=Pv/(nR)

=3.32×5/4×0.083

= 50k

Temp of gas is 50k

$<marquee>❌Mr.Broken❌$

Answer 2

✓✓PV=nRT

✓✓T=PV/nR

✓✓T=3.32bar x 5dm3/ 4.0 mol x 0.083 bar K-1 mol-1

✓✓✓T=50 K

Ans. 50K