Question

calculate the temperature of 6.0 mole of a gas occupying 4dm^3 at 2 bar pressure.
(R = 0.0825 dm^3 k^-1 mol^-1)​

Answer 1

Answer:

T

=

P

V

n

R

=

3.32

abr

×

5

d

m

3

4.0

m

o

l

×

0.083

bar

d

m

3

K

−

1

m

o

l

−

Answer 2

Answer:

ideal gas equation

pV=nRT

p - 2 bars

v - 4dmcube

n - 6

R - 0.825  

Explanation:

subsitute in equation

T = pV/nR

T = 2*4/6*0.825

T= 1.62 K