Question

calculate the temperature of 6.0 moles of a gas occupying 4 decimeter cube at 2 bar pressure​

Answer 1

Explanation:

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Answer 2

Answer:

The temperature, T, of the gas calculated is $16.03K$

Explanation:

Data given,

The given gas's number of moles, n = $6moles$

The given volume of the gas, V = $4dm^{3}$ = $4L$

The given pressure of the gas, P = $2bar$

The temperature of the gas, T =?

Now, we can calculate the temperature by using the ideal gas equation given below:

• $PV =nRT$
• T = $\frac{PV}{nR}$

Here, R = Raydberg's constant = $0.08314 L-bar/K-mol$

After putting the values of n, V, P, and R in the equation, we get:

• T = $\frac{2\times 4}{6\times 0.08314}$
• T = $16.03K$

Hence, the temperature, T, of the gas calculated is $16.03K$.