Calculate the temperature of an object with a peak emittance wavelength of 9.5 µm?
Answers
Answered by
6
Answer: ANS IS (C) 32 C
Explanation:
FORMULA T=2880/9.5=32
Answered by
0
Answer:
305.05 K.
Explanation:
Here the wavelength of the object is given as 9.5µm is given so the value in meter will be 9.5*10^-6. So, we know for black body radiation we get the formulae of emission as wavelength λ*T will be equal to 2.898*10^-3 m.K.
So, on substituting the value of the λ from the question we will get that the value of temperature will be T=2.898*10^-3/9.5*10^-6 which on solving we will get that the temperature will be 305.05 K.
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