Calculate the temperature (T2) at which the rms velocity of gas doubles its value at STP (T1=273 K)
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The temperature at which the rms speed of gas molecules becomes double its value at 0
o
C is :
Easy
Solution
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Correct option is
A
819
o
C
According to the kinetic theory of gases
v
rms
=
3
M
RT
so v
rms
α
T
v
1
v
2
=
T
1
T
2
eq(1)
v
2
=2v
1
T
1
=0
o
C=273K
substitute values back to eq(1)
2=
273
T
2
T
2
=4×273=1092K=819
o
C
T
2
=819
o
C
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