Question

calculate the temperature to which a gas must be heated so that the volume triples without any change in pressure the gas is originally at 57 degree Celsius and having a volume 150 cc

Answer 1

Answer: 990K

Explanation:

Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

$V\propto T$    (At constant pressure and number of moles)

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

$V_1$= initial volume =150 cc

$T_1$= initial temperature =$57^0C=57+273K=330K$

$V_2$= final volume =$3\times 150cc=450cc$

$V_1$= final temperature= ?

$\frac{150cc}{330K}=\frac{450cc}{T_2}$

$T_2=990K$

Answer 2

Answer:

hope it might help you:)