Calculate the tempreture of 4 mole of gas occupying in 5 dm3 at 3.32 bar ( R : 0.083 bar dm3 k-1 mol -1 )
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Use ideal gas equation
PV = nRT
T = PV / (nR)
= (3.32 bar × 5 dm³) / (4 mol × 0.083 bar dm³ / (mol K))
= 50 K
Temperature of gas is 50 Kelvin
PV = nRT
T = PV / (nR)
= (3.32 bar × 5 dm³) / (4 mol × 0.083 bar dm³ / (mol K))
= 50 K
Temperature of gas is 50 Kelvin
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