Calculate the tension.
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a = F/m
By FBD using Newton's 2nd law,
F - T = (M/L) x.a => T = F - (M/L) x. F/M
T = F( 1 - x/L )
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Here is your answer
Let the mass of the rope AB be m.
Acceleration of the rope = a = F/m
Let the force be applied at the end A and the point at a distance x from point A be P .
Tension in the rope at a distance x from end
(at point P )
= Force required to move the remaining part with acceleration a
Linear mass density of the rod = m/l
Mass of the remaining part i.e. part PB = m/l×(l-x)
Force required to move the remaining part mass*acceleration
= m/l×(l-x) ×F/m
Therefore , tension in the rope at a distance x from the
end at which the force is applied is .
F×(l-x)/l
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