Calculate the terminal velocity of an air bubble of radius 5×10^-4m rising in a liquid of viscosity 0.15Ns/m^2. Density of liquid = 900kg/m^3.
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Answer:
Terminal velocity is given as
V
T
=
9
2
r
2
h
(δ−σ)g
∵ no density of air ρ=0
V
T
=
9
2
r
2
h
(σ)g
=
9
2
0.15
(0.4×10
−3
)
2
(900)×9.8
=0.0020 m/s
V
T
=0.20 cm/s
For water
(V
T
)
liq
=(V
T
)
water
V
T
(H
2
O)
(V
T
)
liq
=
σ
2
σ
1
V
T(H
2
O)
=V
T(liq)
×
σ
1
σ
2
=0.002×
997
900
V
T(H
2
O)
=0.18 cm/s
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