Calculate the
The resistance of a conducting wire X of length 1 m is
5ohm.calculate the
resistance of the wire made by the same material whose length is 4 times
and area of cross-section is 5 times that of wire X. (At same
times that of wire x At same temperature
Answers
Answered by
44
- Initial resistance for wire X = 5 ohm = p(L/A)
- Length of new wire = 4 times
- Area of new wire = 5 times
Hence , new resistance be R"
R" = p(L"/A")
=> R" = p(4L/5A)
=> R" = p(L/A) × 4/5
=> R" = 5 × 4/5
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Answered by
19
Answer:
Explanation:
→ Initial resistance for wire X = 5 ohm = p(L/A)
→ Now, length of new wire = 4 times
→ Area of new wire = 5 times
→ Hence , new resistance be R"
→ R" = p(L"/A")
→ R" = p(4L/5A)
→ R" = p(L/A) × 4/5
→ R" = 5 × 4/5
→ R" = 4 ohms.
→ so resistance = 4 ohm
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