Question

Calculate the thrust exerted upon an area of 100cm² by a water column of height 10m(Given:g=10m/s²,density of water=100kg/m³).

Answer it fast.
No spamming.
​

Answer 1

Answer :

To Find :-

$\bullet$ The Thrust exerted !!

Given :-

• Density of water = 100 kg/m³.

• Height of the column = 10 m.

• Area = 100 cm².

• Acceleration due to Gravity = 10m/s².

We know :-

⠀⠀⠀⠀⠀⠀⠀Formula for Upthrust :-

$\underline{\boxed{\bf{F_{B} = V \rho\:g}}}$

Where :-

⠀⠀⠀⠀⠀$\bullet$⠀ρ = Density of the liquid.

⠀⠀⠀⠀⠀$\bullet$⠀V = Volume of the body .

⠀⠀⠀⠀⠀$\bullet$⠀g = Acceleration due to Gravity.

⠀⠀⠀⠀⠀$\bullet$⠀F = Thrust Acting.

⠀⠀⠀⠀⠀⠀⠀⠀Volume of a body :-

$\underline{\boxed{\bf{V = Area \times Height}}}$

Now , using this given information let's try to find the necessary values needed to find the Upthrust .

Concept :-

In the question , the Area and Height is given so by the formula of volume we can find the volume of the body.

But let us convert the area in m² from cm².

We know that ;

⠀⠀⠀⠀⠀⠀⠀⠀⠀1 m² = 100 cm²

So , 100 cm² is 1 m².

Hence, the area is 1 m².

Now , after finding the volume of the body , we can use the formula for Upthrust and by substituting the values in it , we can find the required value.

Solution :-

⠀⠀⠀⠀⠀⠀⠀⠀To find the Volume:-

Using the formula and substituting the values in it , we get :-

$:\implies \bf{V = Area \times Height} \\ \\ \\ :\implies \bf{V = 1 \times 10} \\ \\ \\ \bf{V = 10 } \\ \\ \\ \therefore \bf{Volume = 10 m^{3}}$

Hence, the volume of the body is 10 m³.

Now , with this information we can find the Upthrust on the body.

⠀⠀⠀⠀⠀⠀⠀To Find the Upthrust :-

Using the formula and substituting the values in it, we get :-

$:\implies \bf{F_{B} = V \rho\:g} \\ \\ \\ :\implies \bf{F_{B} = 10 \times 100 \times 10} \\ \\ \\ :\implies \bf{F_{B} = 100 \times 100} \\ \\ \\ :\implies \bf{F_{B} = 10000} \\ \\ \\ \therefore \bf{Upthrust = 10000 N}$

Hence, the Upthrust acting on the body is 10000 N.