Question

calculate the time of descent of a projectile thrown with an initial velocity of 500m/s at an angle of 30° with horizontal.​

Answer 1

$\color{darkblue}\underline{\underline{\sf Given-}}$

• Initial Velocity (u) = 500m/s
• Angle $(\theta)$ = 30°

$\color{darkblue}\underline{\underline{\sf To \: Find-}}$

• Time (T)

━━━━━━━━━━━━━━━━━━━━━━━━━━━

$\color{violet}\bullet\underline{\boxed{\sf T=\dfrac{2usin\theta}{g}}}$

$\implies{\sf T=\dfrac{2×500×sin30°}{10} }$

sin30° = ½

$\implies{\sf T=\dfrac{2×500×1}{10×2}}$

$\color{red}\implies{\sf T=50\:sec}$

$\color{darkblue}\underline{\underline{\sf Answer-}}$

Time of projection is $\color{red}{\sf 50\:sec}$.