calculate the time period and oscillation frequency of a simple pendulum of length 20 cm at a certain place where g =9.8ms-2
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Answer:
T = 2pieunder root l\g
l= 20*10^-2meters
g= 9.8mper sec^-2
T= 2pie *1\70
T= 2pie*1\70
T= pie*1\35
Explanation:
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