Calculate the time period for simple pendulum producing 10 oscillations in 15 seconds
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Answered by
1
10 oscillations in 15 sec
1 oscillation in x sec
CROSS MULTIPLICATION
x=1.5
frequency = 1.5
then TIMEPERIOD= 1/f=0.66sec
1 oscillation in x sec
CROSS MULTIPLICATION
x=1.5
frequency = 1.5
then TIMEPERIOD= 1/f=0.66sec
Answered by
1
Pendulum produces 10 oscillations in 15seconds
1 oscillation = (15/10)seconds
1 oscillation = 1.5seconds
Frequency = 1/T
F=1/1.5
F=0.66Hz
1 oscillation = (15/10)seconds
1 oscillation = 1.5seconds
Frequency = 1/T
F=1/1.5
F=0.66Hz
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