Question

calculate the time period frequency of string in simple pendulum if its length is reduced to half of its original length answer please​

Answer 1

Answer:

As per question, it says that length is reduced to half of the original length i.e. 0.5l

t = (2*pi)*√L/g

t/(2*pi) = √L/g

t^2/(2*3.14)^2 = L/g

t^2*9.8/(6.28)^2 = 1/2

= 9.8t^2/39.25 = 0.5

= 9.8t^2 = 19.625

= t^2 = 2

= t = √2

= t = 1.414

Now, frequency = 1/t

= f = 1/√2

= f = 1/1.414

f = 0.7

It says that if the length of pendulum is reduced to half then, the time period will be reduced 1.414 times and the frequency reduced will be 0.7 times.

Hope this helps.