Physics, asked by debjunior, 9 months ago

Calculate the time period of a second pendulum clock at a height from the earth surface where value of g=4.9 m.s-2.​

Answers

Answered by duttapulok5
2

Explanation:

v=u+at

=>0=-2+4.9t

=>4.9t=2

=>t=2/4.9

Answered by pragnyavengala
1

Answer:

On surface of moon, acceleration due to gravity is g/6. Time period of seconds pendulum on earth is 2 seconds. On Earth ... If the circumference of Newtonia is 51400km, find the mass of the planet. 1 Verified ... If unit of length and time is doubled, the numerical value of g (acceleration due to gravity) will be.

Explanation:

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