Physics, asked by priyanshi1238, 4 months ago

Calculate the time period of a simple pendulum of length 1.2 m when acceleration due to graviy
98 ms^-2.

Answers

Answered by sabitasingh76142

1

Answer:

l=1.12m; g=9.8ms

−2

; T=?

T=2π

g

l

=

7

2×22

9.8

1.12

=

7

44

0.114

=

7

44

×0.338=2.12s

Explanation:

please mark me as brainlist

Answered by Anonymous

2

Answer:

good night

sweet dreams

Previous Question

Next Question

Similar questions

Social Sciences, 1 month ago

the second world war was found between...

Hindi, 1 month ago

भाषा का – रूप बोली कहलाता है...

Psychology, 1 month ago

There is a fear that the whole life may not be spent just in search of a friend...

English, 4 months ago

!:How can an airline survive a government order to ground its entire fleet and shut down for days? After 9/11, all U.S. airlines were faced with this same crisis. One that succeeded through the difficulty was Southwest Airlines, already known for its outstanding customer service. Southwest’s passengers, flight attendants, pilots and ground crews were stranded all across the country after the...

Math, 4 months ago

UL апу рос 12 IS bisecled by that LM = LN. C N P 6. In the figure, PM = PN, PM I AB and PNI AC. Show that AM = AN. B А- M...

History, 10 months ago

to whom did the Chola rulers make land grants and why mention some of the type of land grants given by the Chola king...

Physics, 10 months ago

Difference between Capacitor and battery. Explain...

Physics, 10 months ago

If Ā=i+j+k and B=2i+j find (a) A.B (b) A B...