Question

Calculate the time period of a simple pendulum with length 10m [taking g=10 m/s square]​

Answer 1

Answer:

the length of seconds pendulum is 99.3 cm

Answer 2

Answer:

$2\pi \: s$

Given,

Length = 10 m

gravitational acceleration = 10m/s square

we know that

time period =

$2\pi \sqrt{ \frac{l}{g} }$

So,

$2\pi \sqrt{ \frac{10}{10} }$

$2\pi s$