Question

calculate the time period of simple pendulum of length 0.84 m when g =9.8 ms^-2

Answer 1

Here's Ur answer..
Hope it helps..

Answer 2

Time period of simple pendulum = 2π√(l/g)
= 2π√(0.84/9.8) = 2π√0.0857
= 2π(0.29) = 1.822s