Calculate the time period of simple pendulum of length 1.5 m on the surface of the moon. The acceleration due to gravity on the surface of moon is 1/6 the acceleration due to gravity on earth.[ g = 98 m/s2.
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L = 1.12 m
Acceleration due to gravity on moon = acceleration due to gravity on the earth/6
am=9.8/6
Wkt t= 2/-/(root l /g) = 2*(22/7)* root(1.12*6/9.8)=5.20 s
U can take help of this and do it. It’s of same model
Acceleration due to gravity on moon = acceleration due to gravity on the earth/6
am=9.8/6
Wkt t= 2/-/(root l /g) = 2*(22/7)* root(1.12*6/9.8)=5.20 s
U can take help of this and do it. It’s of same model
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