Question

Calculate the time required to deposit
2 x 10 cm thick layer of silver (density
1.05 g cm-3) on the surface of area 100
by passing a current of 10 A through
-3
ст
silver nitrate solution?
0 125 s
0 115 s.
O 18.7 s
O 27.25 s​

Answer 1

Answer:

125$

Explanation:

Mass of silver required =1.05×80×5×10

−3

=0.42g

By Faraday's law, w=

96500×nf

M

×i×t

where M= Molecular weight, nf=n−factor

In this case, nf=1,M=108g,w=0.42g

∴0.42=

96500×1

108

×3×t

∴t=125 sec.