Question

Calculate the time taken by a 150 w bulb of
consuming 3000 joule of energy


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Answer 1

Given :

• Power of a bulb is 150 W .
• Work Done is equal to 3000 J .

To Find :

• Time Taken .

Solution :

$\longmapsto\tt{Power=150\:w}$

$\longmapsto\tt{Work\:Done=3000\:J}$

Using Formula :

$\longmapsto\tt\boxed{Power=\dfrac{Work\:Done}{Time}}$

Putting Values :

$\longmapsto\tt{150=\dfrac{3000}{t}}$

$\longmapsto\tt{t=\cancel\dfrac{3000}{150}}$

$\longmapsto\tt\bf{t=20\:sec}$

So , The Time taken by the bulb is 20 seconds ..

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Power :

Power is defined as rate of doing work .

$\tt{Power=\dfrac{Work\:Done}{Time}}$

Work Done :

A work is said to be done when a force acted on a body displaces it upto a certain extend .

$\tt{W=F\times{S}}$

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Answer 2

Given:

☄ Power of bulb, P = 150w

☄ Work done, W = 3000Joule

Find:

☄ What is the time taken by bulb

Solution:

☯we, know that☯

$\boxed{\boxed{\boxed{\boxed{\sf P = \dfrac{W}{t}}}}}$

where,

• P = 150w
• W = 3000J

So,

$\to\sf P = \dfrac{W}{t}$

$\Longrightarrow\sf 150 = \dfrac{3000}{t}$

$\Longrightarrow\sf \dfrac{150}{1} = \dfrac{3000}{t}$

$\Longrightarrow\sf 150t = 3000$

$\Longrightarrow\sf t = \cancel{\dfrac{3000}{150}} = 20sec$

$\Longrightarrow\sf t = 20sec$

Hence, the total time taken by the bulb is 20sec

$\rule{300}{2}$