Question

Calculate the time taken by the body performing s.H.M.To cover half the amplitude starting from the extreme position with period two second

Answer 1

Hey mate,

◆ Answer-
t = 0.33 s

◆ Explanation-
# Given-
T = 2 s
x = A/2

# Solution-
Eqn for SHM starting from extremity is -
x = Acos(ωt)

When x = A/2,
A/2 = Acos(ωt)
cos(ωt) = 1/2

Taking inverse-
ωt = π/3
2πt/T = π/3
t = T/6
t = 2/6
t = 0.33 s

Therefore, particle will take 0.33 s in S.H.M. to cover half the amplitude.

Hope it helps...