Calculate the time to deposit 1.27g of copper at cathode when a current of 2A was passed through the solution of cuso4
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W = (A X I X t) ÷ n x 96500
1.27 = (63.5 x 2 x t) ÷ 2 x 96500
t = (1.27 x 2 x 96500) ÷ (2 x 63.5) = 1930 seconds
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