Question

calculate the torque experienced by a coil of dimension 5cm by 2cm having 50 turns and carrying a current 2A placed perpendicular to a magnetic field of 0.005 Telsa.​

Answer 1

Answer:

Correct option is A)

Given : N=100 turns Δt=0.05 s

Change in magnetic field ΔB=0.1−0.05=0.05 T

Area of coil A=0.1×0.05=5×10

−3

m

2

Thus magnitude of change in flux Δϕ=AΔB=5×10

−3

×0.05=2.5×10

−4

Wb

∴ Emf induced E=N

Δt

Δϕ

⟹ E=100×

0.05

2.5×10

−4

=0.5 volts

Answer 2

Answer:

The torque experienced is 0.0005 Nm

Explanation:

We know that ζ = N I A B sin $\theta$

Here, ζ is the Torque that is to be calculated.

         N = number of turns of the coil = 50

          I = current in the coil = 2A

         A = area of the coil = 5cm × 2cm = 0.05m × 0.02m = 0.001m²

         B = Magnetic field = 0.005 T

          $\theta$ = 90°

Substituting the given values in the formula, we get

ζ = 50 × 2 × 0.001 × 0.005 × sin 90°

   = 0.0005 Nm

Therefore the torque experienced is 0.0005 Nm