calculate the torque necessary to produce an angular acceleration of 25rads in a flywheel of mass 50 kg and radius of gyration 50 cm about it's axis
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The torque necessary to produce an angular acceleration of 25 rad/s in a flywheel of mass 50 kg and radius of gyration 50 cm about its axis is τ = 312.5 N-m
Explanation:
Formula: τ = I x α where I is moment of inertia and α is angular acceleration
Radius of gyration k = 50 cm = 0.5 m
Mass "m" = 10 kg
I = m* k^2
I = 50 * (0.5)^2 = 12.5 kg-m^2
Angular acceleration "α" = 25 r.p.s
Torque τ = I x α
Torque τ = 12.5 x 25
Torque τ = 312.5 N-m
Thus, τ = 312.5 N-m
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