calculate the total amount of heat energy required to convert 100 g of ice at - 10 degree Celsius completely into water at 100 degree Celsius. specific heat of ice 2.1J/g/K, specific heat capacity of water = 4.2J/g/K, specific latent heat of ice = 336J/g.
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The amount of heat energy required to convert 100 g of ice is 7.77 x 10^4 J.
Step-by-step explanation:
- Energy required to increase the temperature of water.
- From -10°C to 0°C to convert the ice into water and then further heat is required to raise its temperature from 0°C to 100 ° C.
Energy required = 100 x 2.1 x 10+ 100 x 336 + 100 x 4.2 x 100
Energy required = 2100 + 33600 + 42000
Energy required = 7.77 x 10^4 J
Hence the amount of heat energy required to convert 100 g of ice is 7.77 x 10^4 J.
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