Math, asked by ashnamantony123, 3 days ago

Calculate the total amount to be paid if ₹5500 is borrowed for 3 years at 14% per annum.

Answers

Answered by preeti353615
4

Answer:

The total amount to be paid if ₹5500 is borrowed for 3 years at 14% per annum is ₹7810.

Step-by-step explanation:

Given: Principal = ₹ 5500

Rate = 14%

Time = 3 years

Formula:

SI = \frac{principal \times time \times rate}{100} \\= \frac{5500 \times 3 \times 14}{100} \\= 55  \times 42\\=2310 Rs

Amount = Rs.(Principal + SI)

Amount = Rs.(5500 + 2310)

Amount = Rs.7810

So, amount pay after 3 years is ₹7810.

Answered by Anonymous
22

Information provided with us:

➪ Principal

\implies \sf \:5500\:  Rs

➪Time

\implies \sf \: 3 \: years

➪ Rate of Interest

 \sf\implies \: 14 \: \% \: per \: annum

What we have to calculate

➪The required Total amount

✰Note :

  • First find simple Interest

Formula used

\clubsuit \: \rm  \:Simple \: Interest  :

  \longrightarrow\bigstar \:  \:   \sf\boxed{\bold{\orange{ \bigg(\dfrac{P \times R \times  T}{100}\bigg)}}}\: \: \: \bigstar\\

Where

➡ P = Principle

➡ R = Rate of Interest

➡ T = Time

Now

➡ Substitute the given values in above formula and solve

  \longrightarrow\bigstar \:  \:   \sf\boxed{\bold{\green{ \bigg(\dfrac{5500\times 14 \times  3}{100}\bigg)}}}\: \: \: \bigstar\\

  \longrightarrow\bigstar \:  \:   \sf\boxed{\bold{\red{ \bigg(\dfrac{231000}{100}\bigg)}}}\: \: \: \bigstar\\

  \longrightarrow\bigstar \:  \:   \sf\boxed{\bold{\blue{2,310 \:Rs }}}\: \: \: \bigstar\\

Therefore

  \rm \therefore \: Thus  \: required  \: simple \:    interest\:is

   \implies\bigstar \:  \:   \sf\boxed{\bold{\gray{2,310 \:Rs }}}\: \: \: \bigstar\\

Now

  • ➡ Amount = Principle + Simple Interest

  \longrightarrow\bigstar \:  \:   \sf\boxed{\bold{\pink{\:5,500 + 2,310 \:Rs }}}\: \: \: \bigstar\\

  \longrightarrow\bigstar \:  \:   \sf\boxed{\bold{\purple{7,810 \:Rs }}}\: \: \: \bigstar\\

Therefore

  \rm \therefore \: Thus  \: required  \: amount \:is

   \implies\bigstar \:  \:   \sf\boxed{\bold{\gray{7,810 \:Rs }}}\: \: \: \bigstar\\

Similar questions