Calculate the total cost of running the following electrical devices in the month of September, if the rate of 1 unit of electricity is ` 6.00.
(i) Electric heater of 1000 W for 5 hours daily.
(ii)Electric refrigerator of 400 W for 10 hours daily.
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3
Answer:
w×time ×month /1000 = 1000×5×30/1000 80 kw cost = 80×6.00 48 rs.
for second answr also take same formula 400×10×31/1000=124kw
cost= 124×6= 744rs
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2
It is already known that electric heater consumes 1000 W for 5 hours/day: Amount of 1 unit of electricity is Rs 6. Since, 1KW is used for 5 hr. So, the total amount to be paid = Rs (900 + 720) = Rs 1620.
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