Question

Calculate the total distance covered by the object from the speed-time graph given below:

Answer 1

Total distance covered = Area under the graph

Area of trapezium ABCO = (a+b/2) ×h

height = 30

a = 14

b = 13-5 = 8

Area of trapezium = (8+14/2)×30 = 11×30 = 330m²

Therefore distance covered = 330m²

(assuming the time is in seconds and speed is in m/s)

Cheers!

Answer 2

Answer:

S₁ = Area of triangle

= 1/2 × 5 × 30

= 75 units

S₂ = Area of rectangle

=(13 - 5)×30

=240 units

S₃ = Area of triangle

= 1/2 × (14 - 13) × 30 = 1/2 × 1 × 30

=15 units

S' = S₁ + S₂ + S₃

=75 + 240 + 15 = 330 units

Total distance covered by the object = 330 units