Calculate the total energy emitted when electrons of 1.0 g atom
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Hi there,
We Know,
1λ=R[1n12−1n22]
R= 1.1×107 m−1
For visible region Balmer series is applicable
For Balmer Series : n1=2 n2=3 (Lowest energy)
1λ=1.1×107 m−1[122−132]1λ
=1.1×107 ×5361λ=0.15277×107 m−1λ
=10.15277×107 m−1
=6.546×10−7 m
Energy emitted ΔE=hcλΔE
=6.625×10−34 J sec × 3×108 ms−16.545×10−7 m
=3.037×10−19 J
Energy emitted by 1 g of Hydrogen
=3.037×10−19 J × Avagadro's No.
=3.037×10−19 × 6.022×1023 J
=182.2 kJ
We Know,
1λ=R[1n12−1n22]
R= 1.1×107 m−1
For visible region Balmer series is applicable
For Balmer Series : n1=2 n2=3 (Lowest energy)
1λ=1.1×107 m−1[122−132]1λ
=1.1×107 ×5361λ=0.15277×107 m−1λ
=10.15277×107 m−1
=6.546×10−7 m
Energy emitted ΔE=hcλΔE
=6.625×10−34 J sec × 3×108 ms−16.545×10−7 m
=3.037×10−19 J
Energy emitted by 1 g of Hydrogen
=3.037×10−19 J × Avagadro's No.
=3.037×10−19 × 6.022×1023 J
=182.2 kJ
beetstark1:
Yo !
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