Calculate the total heat generated by a body of mass if
mass (m) of body=100grams
Specific heat (S)=0.10
Initial temperature=30°C
Final temperature=100 C
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Units are in SI system.
Steps:
1) Given,
Mass of Caloriemeter, m = 100g = 0.1kg
Specific Heat of Caloriemeter, S (C) = 0.1 units
Mass of liquid, m. = 0.25 kg
Specific Heat of Liquid, s(L) = 0.4 units
Mass of Ice, = 0.01kg
Latent heat of fusion of Ice, L(f) = 80 units
Specific heat of water, S(w) = 1 units.
2) Heat due to fusion = m L
Heat due to change in T = ms* del(T)
Let the final Equilibrium Temperature be T. Celsius.
Q(net ) = Q(1) + Q(2) + Q(3) + Q(4)
0 = 0.1 * 0.1 (T-30) + 0.25 *0.4 (T-30) + 0.01 * 80
+ 1* 0.01 (T-0)
Multiply by 100 on both sides,
=>0 = T-30 + 10(T-30) + 80 + T
=> 12 T = 250
=> T = 20.83 °C
Therefore, Final Temperature of mixture = 20.83°C
Explanation:
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