Question

Calculate the total KE of the mixture of 4 gm H2 and 4 gm He at 300 K​

Answer 1

Answer:

[HI]=0.778M

Explanation:

We're asked to find the equilibrium concentration of HI with an initial concentration of 1 mol H2and 1 mol I2.
The equilibrium constant expression for this reaction is
Kc=[HI]2[H2][I2]=49
The initial concentrations of both H2 and I2 are
1lmol2lL=0.5M
So our initial concentrations for each species are
Initial:

H2: 0.5M

I2: 0.5M

HI: 0

From the coefficients of the chemical equation, we can predict the changes in concentration with the quantity x:
Change:

H2: −x

I2: −x

HI: +2x

and the final concentrations are the sum of the initial and change:
Final:

H2: 0.5M−x

I2: 0.5M−x

HI: 2x

It's algebra time! Let's plug these into our equilibrium constant expression to start solving for x:
Kc=(2